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                [Usaco2013 Mar]The Cow Run                </h1>
                <p>时间限制：10s&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  空间限制：128MB</p>			</div>
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                                <h3>题目描述</h3><p><p><span style="font-size: medium">Farmer John has forgotten to repair a hole in the fence on his farm, and his N cows (1 &lt;= N &lt;= 1,000) have escaped and gone on a rampage! Each minute a cow is outside the fence, she causes one dollar worth of damage. FJ must visit each cow to install a halter that will calm the cow and stop the damage. Fortunately, the cows are positioned at distinct locations along a straight line on a road outside the farm. FJ knows the location P_i of each cow i (-500,000 &lt;= P_i &lt;= 500,000, P_i != 0) relative to the gate (position 0) where FJ starts. FJ moves at one unit of distance per minute and can install a halter instantly. Please determine the order that FJ should visit the cows so he can minimize the total cost of the damage; you should compute the minimum total damage cost in this case.&nbsp;</span></p>
<p><span style="font-size: medium">题意如OJ1742</span></p></p><hr/><h3>输入格式</h3><p><p><font size="4">&nbsp; * Line 1: The number of cows, N. * Lines 2..N+1: Line i+1 contains the integer P_i. </font></p>
<p><span style="font-size: medium">见OJ1742</span></p></p><hr/><h3>输出格式</h3><p><p><font size="4">* Line 1: The minimum total cost of the damage.&nbsp;</font></p></p><hr/><h3>样例输入</h3><pre>4
-2
-12
3
7

</pre><hr/><h3>样例输出</h3><pre>50

 OUTPUT DETAILS: The optimal visit order is -2, 3, 7, -12. FJ arrives at position -2 in 2 minutes for a total of 2 dollars in damage for that cow. He then travels to position 3 (distance: 5) where the cumulative damage is 2 + 5 = 7 dollars for that cow. He spends 4 more minutes to get to 7 at a cost of 7 + 4 = 11 dollars for that cow. Finally, he spends 19 minutes to go to -12 with a cost of 11 + 19 = 30 dollars. The total damage is 2 + 7 + 11 + 30 = 50 dollars. 

 
</pre><hr/><h3>提示</h3><p>没有写明提示</p><hr/><h3>题目来源</h3><p>Gold</p>
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